5b^2-19b+18=0

Solution for 5b^2-19b+18=0 equation:

Simplifying
5b2 + -19b + 18 = 0

Reorder the terms:
18 + -19b + 5b2 = 0

Solving
18 + -19b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(9 + -5b)(2 + -1b) = 0

Subproblem 1
Set the factor '(9 + -5b)' equal to zero and attempt to solve:

Simplifying
9 + -5b = 0

Solving
9 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -5b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -5b = 0 + -9
-5b = 0 + -9

Combine like terms: 0 + -9 = -9
-5b = -9

Divide each side by '-5'.
b = 1.8

Simplifying
b = 1.8
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {1.8, 2}